For
sin 2 x + cos x = 0 , \displaystyle {\sin{{2}}}{x}+{\cos{{x}}}={0}, sin 2 x + cos x = 0 ,
use a double-angle or half-angle formula to simplify the equation and then
find all solutions of the equation
in the interval
[ 0 , 2 π ) . \displaystyle {\left[{0},{2}\pi\right)}. [ 0 , 2 π ) .
The answers are
x 1 = \displaystyle {x}_{{1}}= x 1 = Preview Question 6 Part 1 of 4 ,
x 2 = \displaystyle {x}_{{2}}= x 2 = Preview Question 6 Part 2 of 4 ,
x 3 = \displaystyle {x}_{{3}}= x 3 = Preview Question 6 Part 3 of 4 and
x 4 = \displaystyle {x}_{{4}}= x 4 = Preview Question 6 Part 4 of 4
with
x 1 < x 2 < x 3 < x 4 \displaystyle {x}_{{1}}\lt{x}_{{2}}\lt{x}_{{3}}\lt{x}_{{4}} x 1 < x 2 < x 3 < x 4 .
Submit Try a similar question
[more..]
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)