Using the Law of Sines to solve the triangle if
∠ A = 40 ∘ , ∠ C = 65 ∘ , b = 24 : \displaystyle \angle{A}={40}^{\circ},\angle{C}={65}^{\circ},{b}={24}: ∠ A = 40 ∘ , ∠ C = 65 ∘ , b = 24 : ∠ B \displaystyle \angle{B} ∠ B is
Preview Question 6 Part 1 of 3 degrees;
a = \displaystyle {a}= a = Preview Question 6 Part 2 of 3 ;
c = \displaystyle {c}= c = Preview Question 6 Part 3 of 3 ;
You may round to two decimal places.
Assume
∠ A \displaystyle \angle{A} ∠ A is opposite side
a \displaystyle {a} a ,
∠ B \displaystyle \angle{B} ∠ B is opposite side
b \displaystyle {b} b , and
∠ C \displaystyle \angle{C} ∠ C is opposite side
c \displaystyle {c} c .
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Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)