Using the Law of Sines to solve the all possible triangles if $\displaystyle \angle{A}={118}^{\circ},{a}={28},{b}={10}.$
If no answer exists, enter DNE for all answers.
$\displaystyle \angle{B}$ is Preview Question 6 Part 1 of 3   degrees;
$\displaystyle \angle{C}$ is Preview Question 6 Part 2 of 3   degrees;
$\displaystyle {c}=$ Preview Question 6 Part 3 of 3   ;


Round to two decimal places as needed.
Assume $\displaystyle \angle{A}$ is opposite side $\displaystyle {a}$, $\displaystyle \angle{B}$ is opposite side $\displaystyle {b}$, and $\displaystyle \angle{C}$ is opposite side $\displaystyle {c}$.