Solve the following system of equations with the substitution method:

{x+2y=13x2y=4\displaystyle {\left\lbrace\begin{array}{ccc} {x}+{2}{y}&=&{1}\\-{3}{x}-{2}{y}&=&{4}\end{array}\right.}

Answer: (x,y)=\displaystyle {\left({x},{y}\right)}= (,)
Preview x\displaystyle {x}:  
Preview y\displaystyle {y}:  


Enter your answers as integers or as reduced fractions in the form A/B.