Simplify the following completely:

A) $\displaystyle \sqrt{{{25}{x}^{{6}}}}\cdot\sqrt{{{5}{x}^{{7}}}}$

Answer: $\displaystyle \sqrt{{{25}{x}^{{6}}}}\cdot\sqrt{{{5}{x}^{{7}}}}={A}\sqrt{{{B}}}$, where
$\displaystyle {A}=$ and
$\displaystyle {B}=$

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B) $\displaystyle \sqrt{{{12}{x}^{{8}}}}\cdot\sqrt{{{6}{x}^{{4}}}}$

Answer: $\displaystyle \sqrt{{{12}{x}^{{8}}}}\cdot\sqrt{{{6}{x}^{{4}}}}={A}\sqrt{{{B}}}$, where
$\displaystyle {A}=$ and
$\displaystyle {B}=$

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