∂∂x2e9xsin⁡(4y) =\displaystyle \frac{{\partial}}{{\partial{x}}}{2}{e}^{{{9}{x}}}{\sin{{\left({4}{y}\right)}}}\ =  
∂∂y2e9xsin⁡(4y) =\displaystyle \frac{{\partial}}{{\partial{y}}}{2}{e}^{{{9}{x}}}{\sin{{\left({4}{y}\right)}}}\ =  

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