Use the midpoint rule with n = 3 to approximate
∫
1
4
sin
(
x
)
x
d
x
\displaystyle {\int_{{1}}^{{4}}}\frac{{\sin{{\left({x}\right)}}}}{{x}}{\left.{d}{x}\right.}
∫
1
4
x
sin
(
x
)
d
x
.
∫
1
4
sin
(
x
)
x
d
x
≈
\displaystyle {\int_{{1}}^{{4}}}\frac{{\sin{{\left({x}\right)}}}}{{x}}{\left.{d}{x}\right.}\approx
∫
1
4
x
sin
(
x
)
d
x
≈
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Question 6
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