Use the trapezoidal rule with n = 5 to approximate
∫
1
5
sin
(
x
)
x
d
x
\displaystyle {\int_{{1}}^{{5}}}\frac{{\sin{{\left({x}\right)}}}}{{x}}{\left.{d}{x}\right.}
∫
1
5
x
sin
(
x
)
d
x
.
∫
1
5
sin
(
x
)
x
d
x
≈
\displaystyle {\int_{{1}}^{{5}}}\frac{{\sin{{\left({x}\right)}}}}{{x}}{\left.{d}{x}\right.}\approx
∫
1
5
x
sin
(
x
)
d
x
≈
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Question 6
Keep at least 2 decimal places accuracy in your final answer
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Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter DNE for Does Not Exist, oo for Infinity