Use Simpson's rule with n = 6 to approximate
ln
(
10
)
=
∫
1
10
1
x
d
x
\displaystyle {\ln{{\left({10}\right)}}}={\int_{{1}}^{{10}}}\frac{{1}}{{x}}{\left.{d}{x}\right.}
ln
(
10
)
=
∫
1
10
x
1
d
x
.
1
2
3
4
5
6
7
8
9
10
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1
ln
(
10
)
≈
\displaystyle {\ln{{\left({10}\right)}}}\approx
ln
(
10
)
≈
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Question 6
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