Evaluate
∫
1
6
+
e
−
10
x
d
x
\displaystyle \int\frac{{1}}{{{6}+{e}^{{-{10}{x}}}}}{\left.{d}{x}\right.}
∫
6
+
e
−
10
x
1
d
x
.
∫
1
6
+
e
−
10
x
d
x
\displaystyle \int\frac{{1}}{{{6}+{e}^{{-{10}{x}}}}}{\left.{d}{x}\right.}
∫
6
+
e
−
10
x
1
d
x
=
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Question 6
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