Find sin(2x)3dx\displaystyle \int{{\sin{{\left({2}{x}\right)}}}^{{3}}{\left.{d}{x}\right.}}
First use a Pythagorean identity to transform the integrand sin(2x)3\displaystyle {{\sin{{\left({2}{x}\right)}}}^{{3}}} into  
Then integrate sin(2x)3dx\displaystyle \int{{\sin{{\left({2}{x}\right)}}}^{{3}}{\left.{d}{x}\right.}} =   + C