The partial fraction decomposition of 236x2+258x+5428x3+31x2+6x\displaystyle \frac{{{236}{x}^{{2}}+{258}{x}+{54}}}{{{28}{x}^{{3}}+{31}{x}^{{2}}+{6}{x}}} equals  
Now integrate.
236x2+258x+5428x3+31x2+6xdx=\displaystyle \int\frac{{{236}{x}^{{2}}+{258}{x}+{54}}}{{{28}{x}^{{3}}+{31}{x}^{{2}}+{6}{x}}}{\left.{d}{x}\right.}=   + C
Note: You must enter |w| as abs(w).