The partial fraction decomposition of
143 x 2 + 194 x + 63 56 x 3 + 73 x 2 + 21 x \displaystyle \frac{{{143}{x}^{{2}}+{194}{x}+{63}}}{{{56}{x}^{{3}}+{73}{x}^{{2}}+{21}{x}}} 56 x 3 + 73 x 2 + 21 x 143 x 2 + 194 x + 63 equals
Preview Question 6 Part 1 of 2
Now integrate.
∫ 143 x 2 + 194 x + 63 56 x 3 + 73 x 2 + 21 x d x = \displaystyle \int\frac{{{143}{x}^{{2}}+{194}{x}+{63}}}{{{56}{x}^{{3}}+{73}{x}^{{2}}+{21}{x}}}{\left.{d}{x}\right.}= ∫ 56 x 3 + 73 x 2 + 21 x 143 x 2 + 194 x + 63 d x = Preview Question 6 Part 2 of 2
+ C
Note: You must enter |w| as abs(w).
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Enter your answer as an expression. Example: 3x^2+1, x/5, (a+b)/c