The partial fraction decomposition of
236 x 2 + 258 x + 54 28 x 3 + 31 x 2 + 6 x \displaystyle \frac{{{236}{x}^{{2}}+{258}{x}+{54}}}{{{28}{x}^{{3}}+{31}{x}^{{2}}+{6}{x}}} 28 x 3 + 31 x 2 + 6 x 236 x 2 + 258 x + 54 equals
Preview Question 6 Part 1 of 2
Now integrate.
∫ 236 x 2 + 258 x + 54 28 x 3 + 31 x 2 + 6 x d x = \displaystyle \int\frac{{{236}{x}^{{2}}+{258}{x}+{54}}}{{{28}{x}^{{3}}+{31}{x}^{{2}}+{6}{x}}}{\left.{d}{x}\right.}= ∫ 28 x 3 + 31 x 2 + 6 x 236 x 2 + 258 x + 54 d x = Preview Question 6 Part 2 of 2
+ C
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Be sure your variables match those in the question