The partial fraction decomposition of 4x2+45x+1081x3+12x2+36x\displaystyle \frac{{{4}{x}^{{2}}+{45}{x}+{108}}}{{{1}{x}^{{3}}+{12}{x}^{{2}}+{36}{x}}} equals  
Now integrate.
4x2+45x+1081x3+12x2+36xdx=\displaystyle \int\frac{{{4}{x}^{{2}}+{45}{x}+{108}}}{{{1}{x}^{{3}}+{12}{x}^{{2}}+{36}{x}}}{\left.{d}{x}\right.}=   + C
Note: You must enter |w| as abs(w).