For the series
∑ n = 1 ∞ ( − 1 ) n 7 n 0.5 + 3 \displaystyle {\sum_{{{n}={1}}}^{\infty}}\frac{{\left(-{1}\right)}^{{n}}}{{{7}{n}^{{0.5}}+{3}}} n = 1 ∑ ∞ 7 n 0.5 + 3 ( − 1 ) n calculate the sum of the first 3 terms,
S 3 \displaystyle {S}_{{3}} S 3 .
S 3 = \displaystyle {S}_{{3}}= S 3 = Preview Question 6 Part 1 of 2
Include several decimals in your answer.
Now find a bound for the error.
|error|
≤ \displaystyle \le ≤ Preview Question 6 Part 2 of 2 Submit Try a similar question
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Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)