To evaluate the indefinite integral
∫ 8 x + 5 7 x + 3.5 d x \displaystyle \int\frac{{{8}{x}+{5}}}{{{7}{x}+{3.5}}}{\left.{d}{x}\right.} ∫ 7 x + 3.5 8 x + 5 d x , first do long division.
Divide
8 x + 5 \displaystyle {8}{x}+{5} 8 x + 5 by
7 x + 3.5 \displaystyle {7}{x}+{3.5} 7 x + 3.5 to obtain a quotient of
Preview Question 6 Part 1 of 3 and a remainder of
Preview Question 6 Part 2 of 3 .
Then
∫ 8 x + 5 7 x + 3.5 d x \displaystyle \int\frac{{{8}{x}+{5}}}{{{7}{x}+{3.5}}}{\left.{d}{x}\right.} ∫ 7 x + 3.5 8 x + 5 d x =
Preview Question 6 Part 3 of 3
+ C
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