Let C be the curve $\displaystyle {y}={3}\sqrt{{{x}}}$ for $\displaystyle {2.6}\le{x}\le{4.4}$.

Find the surface area of revolution about the x-axis of R.

Surface area = $\displaystyle {\int_{{2.6}}^{{4.4}}}{f{{\left({x}\right)}}}\ {\left.{d}{x}\right.}$ where
f( x ) = Preview Question 6 Part 1 of 2  
Now integrate to find surface area = $\displaystyle {\int_{{2.6}}^{{4.4}}}{f{{\left({x}\right)}}}\ {\left.{d}{x}\right.}$ = Preview Question 6 Part 2 of 2