The series
∑
k
=
1
∞
3
(
−
1
)
k
0.7
−
0.8
/
k
\displaystyle {\sum_{{{k}={1}}}^{\infty}}{3}{\left(-{1}\right)}^{{k}}{0.7}^{{-{0.8}/{k}}}
k
=
1
∑
∞
3
(
−
1
)
k
0.7
−
0.8
/
k
converges
diverges
.
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