For the function f( x ) = 5x2+2x1\displaystyle {5}{x}^{{2}}+{2}{x}-{1}, find the value of the difference quotient f(x+h)f(x)h\displaystyle \frac{{{f{{\left({x}+{h}\right)}}}-{f{{\left({x}\right)}}}}}{{h}} for x = -5 and h = 0.1, 0.01 and 0.001
f(4.9)f(5).1\displaystyle \frac{{{f{{\left(-{4.9}\right)}}}-{f{{\left(-{5}\right)}}}}}{{.1}} =  
f(4.99)f(5).01\displaystyle \frac{{{f{{\left(-{4.99}\right)}}}-{f{{\left(-{5}\right)}}}}}{{.01}} =  
f(4.999)f(5).001\displaystyle \frac{{{f{{\left(-{4.999}\right)}}}-{f{{\left(-{5}\right)}}}}}{{.001}} =