1234-1-2-3-42
For the above function f( x ) = 2⋅0.95x\displaystyle {2}\cdot{0.95}^{{x}}, estimate f′(x)\displaystyle {f}'{\left({x}\right)} using h = 0.001 for the following three values.
f′(−1.75)\displaystyle {f}'{\left(-{1.75}\right)} =  
f′(1)\displaystyle {f}'{\left({1}\right)} =  
f′(2.75)\displaystyle {f}'{\left({2.75}\right)} =  

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