Let
f
(
x
)
=
1
x
+
8
\displaystyle {f{{\left({x}\right)}}}={\frac{{{1}}}{{{x}+{8}}}}
f
(
x
)
=
x
+
8
1
f
−
1
(
x
)
=
\displaystyle {{f}^{{-{1}}}{\left({x}\right)}}=
f
−
1
(
x
)
=
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