Let
f
(
x
)
=
{
m
x
−
5
if
x
<
−
3
x
2
+
6
x
−
2
if
x
≥
−
3
\displaystyle {f{{\left({x}\right)}}}={\left\lbrace\begin{array}{ccc} {m}{x}-{5}&\text{if}&{x}<-{3}\\{x}^{{2}}+{6}{x}-{2}&\text{if}&{x}\geq-{3}\end{array}\right.}
f
(
x
)
=
{
m
x
−
5
x
2
+
6
x
−
2
if
if
x
<
−
3
x
≥
−
3
If
f
(
x
)
\displaystyle {f{{\left({x}\right)}}}
f
(
x
)
is a function which is continuous everywhere, then we must have
m
=
\displaystyle {m}=
m
=
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\displaystyle
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter DNE for Does Not Exist, oo for Infinity