If
f ( x ) = 2 x 2 − 6 x + 3 \displaystyle {f{{\left({x}\right)}}}={2}{x}^{{2}}-{6}{x}+{3} f ( x ) = 2 x 2 − 6 x + 3 , find
f ′ ( 0 ) \displaystyle {f}'{\left({0}\right)} f ′ ( 0 ) .
Preview Question 6 Part 1 of 3
Use this to find the equation of the tangent line to the parabola
y = 2 x 2 − 6 x + 3 \displaystyle {y}={2}{x}^{{2}}-{6}{x}+{3} y = 2 x 2 − 6 x + 3
at the point
( 0 , 3 ) \displaystyle {\left({0},{3}\right)} ( 0 , 3 ) .
The equation of this tangent line can be written in the form
y = m x + b \displaystyle {y}={m}{x}+{b} y = m x + b
where
m \displaystyle {m} m is:
Preview Question 6 Part 2 of 3
and where
b \displaystyle {b} b is:
Preview Question 6 Part 3 of 3
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Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4) Enter DNE for Does Not Exist, oo for Infinity
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4) Enter DNE for Does Not Exist, oo for Infinity
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4) Enter DNE for Does Not Exist, oo for Infinity