Find the derivative of the function
g
(
x
)
=
(
x
2
−
2
x
−
3
)
e
x
\displaystyle {g{{\left({x}\right)}}}={\left({x}^{{2}}-{2}{x}-{3}\right)}{e}^{{x}}
g
(
x
)
=
(
x
2
−
2
x
−
3
)
e
x
g
′
(
x
)
=
\displaystyle {g}'{\left({x}\right)}=
g
′
(
x
)
=
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