If f(x)=7x2+5x+4x\displaystyle {f{{\left({x}\right)}}}={\frac{{{7}{x}^{{2}}+{5}{x}+{4}}}{{\sqrt{{{x}}}}}}, then:

f(x)\displaystyle {f}'{\left({x}\right)} =  

f(5)\displaystyle {f}'{\left({5}\right)} =