Given the equation below, find dydx\displaystyle \frac{{{\left.{d}{y}\right.}}}{{{\left.{d}{x}\right.}}}.
14x8+9x56y+y5=4\displaystyle -{14}{x}^{{8}}+{9}{x}^{{56}}{y}+{y}^{{5}}=-{4}


dydx=\displaystyle \frac{{{\left.{d}{y}\right.}}}{{{\left.{d}{x}\right.}}}=  

Now, find the equation of the tangent line to the curve at (1, 1). Write your answer in mx+b\displaystyle {m}{x}+{b} format

y=\displaystyle {y}=