If
x
2
25
+
y
2
16
=
1
\displaystyle {\frac{{{x}^{{2}}}}{{{25}}}}+{\frac{{{y}^{{2}}}}{{{16}}}}={1}
25
x
2
+
16
y
2
=
1
and
y
(
2
)
=
3.67
\displaystyle {y}{\left({2}\right)}={3.67}
y
(
2
)
=
3.67
, find
y
′
(
2
)
\displaystyle {y}'{\left({2}\right)}
y
′
(
2
)
by implicit differentiation.
y
′
(
2
)
\displaystyle {y}'{\left({2}\right)}
y
′
(
2
)
=
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