Find the slope of the tangent line to the curve
3
x
2
−
4
x
y
+
2
y
3
=
67
\displaystyle {3}{x}^{{2}}-{4}{x}{y}+{2}{y}^{{3}}={67}
3
x
2
−
4
x
y
+
2
y
3
=
67
at the point
(
−
3
,
2
)
\displaystyle {\left(-{3},{2}\right)}
(
−
3
,
2
)
.
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\displaystyle
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter DNE for Does Not Exist, oo for Infinity