If
f
(
x
)
=
(
8
x
−
4
)
4
⋅
(
7
x
2
+
7
)
3
\displaystyle {f{{\left({x}\right)}}}={\left({8}{x}-{4}\right)}^{{{4}}}\cdot{\left({7}{x}^{{2}}+{7}\right)}^{{{3}}}
f
(
x
)
=
(
8
x
−
4
)
4
⋅
(
7
x
2
+
7
)
3
, find
f
′
(
x
)
\displaystyle {f}'{\left({x}\right)}
f
′
(
x
)
using logarithmic differentiation.
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