If
f
(
x
)
=
7
−
cosh
x
9
+
cosh
x
\displaystyle {f{{\left({x}\right)}}}={\frac{{{7}-{\cosh{{x}}}}}{{{9}+{\cosh{{x}}}}}}
f
(
x
)
=
9
+
cosh
x
7
−
cosh
x
then
f
′
(
x
)
=
\displaystyle {f}'{\left({x}\right)}=
f
′
(
x
)
=
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