If
f
(
x
)
=
e
cosh
(
4
x
)
\displaystyle {f{{\left({x}\right)}}}={e}^{{{\cosh{{\left({4}{x}\right)}}}}}
f
(
x
)
=
e
c
o
s
h
(
4
x
)
then
f
′
(
x
)
=
\displaystyle {f}'{\left({x}\right)}=
f
′
(
x
)
=
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