A cannon ball is launched into the air with an upward velocity of 172 feet per second, from a 4-foot tall cannon. The height h\displaystyle {h} of the cannon ball after t\displaystyle {t} seconds can be found using the equation h=16t2+172t+4\displaystyle {h}=-{16}{t}^{{2}}+{172}{t}+{4}.

Approximately how long will it take for the cannon ball to be 290 feet high? Round answers to the nearest tenth if necessary.
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How long long will it take to hit the ground?
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