f
(
x
)
=
{
x
2
+
1
if
x <= 1
3
⋅
x
+
C
if
x
>
1
\displaystyle {f{{\left({x}\right)}}}={\left\lbrace\begin{array}{c} {x}^{{2}}+{1}{\quad\text{if}\quad}\text{x <= 1}\\{3}\cdot{x}+{C}{\quad\text{if}\quad}{x}>{1}\end{array}\right.}
f
(
x
)
=
{
x
2
+
1
if
x <= 1
3
⋅
x
+
C
if
x
>
1
What value of C will make this function continuous at x = 1?
C
=
\displaystyle {C}=
C
=
(Hint: For a function to be continuous at x=a, the left limit must equal the right limit as x->a.)
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