Write the indefinite integral below


\displaystyle \int 63x+6\displaystyle \frac{{6}}{\sqrt{{{3}\cdot{x}+{6}}}} dx =   + C



Input x^2 for x2\displaystyle {x}^{{2}}, x^3 for x3\displaystyle {x}^{{3}}, sqrt(x+1) for x+1\displaystyle \sqrt{{{x}+{1}}}

ln(x+1) for the natural logarithm of x+1

Coefficients in your answer can be fractions or decimals.