Make the substitution u =
8+5⋅ex
and then rewrite the integral
in terms of u and du.
The original integral is
∫ 15⋅ex⋅(8+5⋅ex)5 dx
The new integral (in terms of u and du) is
∫
Type
sin(x) for
sin(x) ,
cos(x) for
cos(x), and so on.
Use
x^2 for
x2,
(x+2)^3 for
(x+2)3,
sqrt(x) for
x,
Use
( sin(x) )^2 to square sin(x).