Partial Fraction Decomposition Algebra Practice



Solve for A and B and C.

0x2+26x116\displaystyle {0}\cdot{x}^{{2}}+{26}\cdot{x}-{116} = A(x6)(x+4)+B(x6)(x7)+C(x7)(x+4)\displaystyle {A}\cdot{\left({x}-{6}\right)}\cdot{\left({x}+{4}\right)}+{B}\cdot{\left({x}-{6}\right)}\cdot{\left({x}-{7}\right)}+{C}\cdot{\left({x}-{7}\right)}\cdot{\left({x}+{4}\right)}



A =

B =

C =

Enter each answer as a whole number (like -4, 0, or 253)

or a fraction (like 1/4, -2/5 or 11/7).