Partial Fraction Decomposition Algebra Practice



Solve for A and B and C.

2x213x+20\displaystyle {2}\cdot{x}^{{2}}-{13}\cdot{x}+{20} = A(x2+2)+(Bx+C)(x+5)\displaystyle {A}\cdot{\left({x}^{{2}}+{2}\right)}+{\left({B}\cdot{x}+{C}\right)}\cdot{\left({x}+{5}\right)}

A =

B =

C =

Enter each answer as a whole number (like -4, 0, or 253)

or a fraction (like 1/4, -2/5 or 11/7).