Solve the unknown in the following equation: 2x32x2+8x+8=0\displaystyle -{2}{x}^{{3}}-{2}{x}^{{2}}+{8}{x}+{8}={0}

Find one zero for this polynomial:

The factor of the polynomial based on the above zero:

   
  (\displaystyle -{(} )\displaystyle {)}
     
    (\displaystyle -{(} )\displaystyle {)}
       
      (\displaystyle -{(} )\displaystyle {)}
         

(\displaystyle {(} )×(\displaystyle {)}\times{(} )=0\displaystyle {)}={0}

x=\displaystyle {x}=