Give the general solution for the following trigonometric equation.

133cos(β)=68\displaystyle -{133}{\cos{{\left(\beta\right)}}}=-{68}

  *

*single trig ratio, equal to a constant (as a fraction)

r.a.=\displaystyle {r}.{a}.=

β=\displaystyle \beta=   where kZ\displaystyle {k}\in{Z}

orβ=\displaystyle {\quad\text{or}\quad}\beta=   where kZ\displaystyle {k}\in{Z}