Rewrite the expression
ln
(
a
+
b
)
+
3
ln
(
a
−
b
)
−
4
ln
c
\displaystyle {\ln{{\left({a}+{b}\right)}}}+{3}{\ln{{\left({a}-{b}\right)}}}-{4}{\ln{{c}}}
ln
(
a
+
b
)
+
3
ln
(
a
−
b
)
−
4
ln
c
as a single logarithm
ln
A
\displaystyle {\ln{{A}}}
ln
A
. Then the function
A
=
\displaystyle {A}=
A
=
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