Given that f(x)=x2−2x\displaystyle {f{{\left({x}\right)}}}={x}^{{2}}-{2}{x} and g(x)=x+1\displaystyle {g{{\left({x}\right)}}}={x}+{1}, find
(a) (f+g)(1)\displaystyle {\left({f}+{g}\right)}{\left({1}\right)}=  
(b) (f−g)(1)\displaystyle {\left({f}-{g}\right)}{\left({1}\right)}=  
(c) (fg)(1)\displaystyle {\left({f}{g}\right)}{\left({1}\right)}=  
(d) (fg)(1)\displaystyle {\left(\frac{{f}}{{g}}\right)}{\left({1}\right)}=  

License