Suppose a product's revenue function is given by R(q)=6q2+600q\displaystyle {R}{\left({q}\right)}=-{6}{q}^{{2}}+{600}{q}, where R(q)\displaystyle {R}{\left({q}\right)} is in dollars and q\displaystyle {q} is units sold.

Find a numeric value for the marginal revenue at 13\displaystyle {13} unitsand record your result in the box below.

Answer: MR(13)=\displaystyle {M}{R}{\left({13}\right)}= $perunit\displaystyle \${p}{e}{r}{u}{n}{i}{t}