Evaluate the integral
∫
0
6
(
1
+
8
x
3
)
d
x
=
\displaystyle {\int_{{0}}^{{6}}}{\left({1}+{8}{x}^{{3}}\right)}{\left.{d}{x}\right.}=
∫
0
6
(
1
+
8
x
3
)
d
x
=
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