Find
∫
(
−
2
x
3
−
2
x
+
4
x
3
+
6
x
)
d
x
\displaystyle \int{\left(-{2}{x}^{{3}}-\frac{{2}}{{x}}+\frac{{4}}{{x}^{{3}}}+{6}\sqrt{{{x}}}\right)}{\left.{d}{x}\right.}
∫
(
−
2
x
3
−
x
2
+
x
3
4
+
6
x
)
d
x
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Question 6
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