Let f(x)=xx+7.\displaystyle {f{{\left({x}\right)}}}=\frac{{x}}{{{x}+{7}}}. Find the values of x\displaystyle {x} where f(x)=6\displaystyle {f}'{\left({x}\right)}={6}.

Give exact answers (not decimal approximations).


The greater solution is x=\displaystyle {x}=  
The lesser solution is x=\displaystyle {x}=