12345-1-2-3-4-5π/2π3π/22πx

The graph of the function f(x)=sec⁡x\displaystyle {f{{\left({x}\right)}}}={\sec{{x}}} is given above for the interval x∈[0,2π]\displaystyle {x}\in{\left[{0},{2}\pi\right]} ONLY.

Determine the one-sided limit. Then indicate the equation of the vertical asymptote.

Find lim⁡x→(π2)− f(x)=\displaystyle \lim_{{{x}\to{\left(\frac{\pi}{{2}}\right)}^{{-}}}}\ {f{{\left({x}\right)}}}=  

This indicates the equation of a vertical asymptote is x=\displaystyle {x}=   .

Find lim⁡x→(3π2)+ f(x)=\displaystyle \lim_{{{x}\to{\left(\frac{{{3}\pi}}{{2}}\right)}^{+}}}\ {f{{\left({x}\right)}}}=  

This indicates the equation of a vertical asymptote is x=\displaystyle {x}=   .

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