If
f
(
x
)
=
∫
x
12
t
4
d
t
\displaystyle {f{{\left({x}\right)}}}={\int_{{x}}^{{{12}}}}{t}^{{4}}{\left.{d}{t}\right.}
f
(
x
)
=
∫
x
12
t
4
d
t
then
f
′
(
x
)
=
\displaystyle {f}'{\left({x}\right)}=
f
′
(
x
)
=
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