Find all the values of x such that the given series would converge.
n=1(x3)n3n\displaystyle {\sum_{{{n}={1}}}^{{\infty}}}{\frac{{{\left({x}-{3}\right)}^{{n}}}}{{{3}^{{n}}}}}
The series is convergent
from x\displaystyle {x} =   , left end included (enter Y or N):
to x\displaystyle {x} =   , right end included (enter Y or N):