Differentiate:
f
(
x
)
=
ln
(
x
2
−
6
x
3
)
\displaystyle {f{{\left({x}\right)}}}={\ln{{\left(\frac{{{x}^{{2}}-{6}}}{{x}^{{3}}}\right)}}}
f
(
x
)
=
ln
(
x
3
x
2
−
6
)
f
′
(
x
)
\displaystyle {f}'{\left({x}\right)}
f
′
(
x
)
=
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