Use the quadratic formula to solve $\displaystyle {9}{t}^{{2}}+{12}{t}-{23}={0}.$

You will get two answers, $\displaystyle {t}_{{1}}$ and $\displaystyle {t}_{{2}}$ where $\displaystyle {t}_{{1}}<{t}_{{2}}.$ Enter those solutions in the boxes below, with $\displaystyle {t}_{{1}}$ in the left box and $\displaystyle {t}_{{2}}$ in the right box. Your answers must have your radicals simplified as much as possible. For example, if $\displaystyle {t}=\frac{{-{5}\pm\sqrt{{{15}}}}}{{4}}$ you enter
(-5-sqrt(15))/4 on the left and (-5+sqrt(15))/4 on the right.
Note the important placement of parentheses! Use the PREVIEW button!

$\displaystyle {t}_{{1}}=$ $\displaystyle \lt$ $\displaystyle ={t}_{{2}}$
Note $\displaystyle {t}_{{1}}$ must be the smaller solution.
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