If g(2) =
6
\displaystyle {6}
6
and g'(2) =
−
6
\displaystyle -{6}
−
6
and
f
(
x
)
=
[
g
(
x
)
]
3
\displaystyle {f{{\left({x}\right)}}}={\left[{g{{\left({x}\right)}}}\right]}^{{3}}
f
(
x
)
=
[
g
(
x
)
]
3
, find
f
′
(
2
)
\displaystyle {f}'{\left({2}\right)}
f
′
(
2
)
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\displaystyle
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter DNE for Does Not Exist, oo for Infinity